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mission impossible: simply getting the actual supertype of a type in python.
![L = []
for i in range(10):
def f():
return i
L.append(f)
for f in L:
print(f())](https://cdn.masto.host/mastodongamedevplace/media_attachments/files/114/149/041/356/060/898/original/80850ead5fa89555.png "L = []
for i in range(10):
def f():
return i
L.append(f)
for f in L:
print(f())")
@lritter Since you're asking the question, there has to be a catch - so it's likely not 0 1 2 3 4 5 6 7 8 9, but 9 9 9 9 9 9 9 9 9 9, because the `f()` function captures only the most recent value of `i`. Another level of indirection would solve this.
(No peeking. Yet.)