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Leonard Ritter @lritter@mastodon.gamedev.place
mission impossible: simply getting the actual supertype of a type in python.
![L = []
for i in range(10):
def f():
return i
L.append(f)
for f in L:
print(f())](https://cdn.masto.host/mastodongamedevplace/media_attachments/files/114/149/041/356/060/898/original/80850ead5fa89555.png "L = []
for i in range(10):
def f():
return i
L.append(f)
for f in L:
print(f())")
bbk9 
@lritter Sorry, I checked out at the misaligned square brackets 
@balint i put them in to irritate specifically you
@lritter I can’t believe you’ve done this
@lritter lets make it worse by combining it with my other favourite footgun pattern
![def gen_append_i_to_a(i, a = []):
def append_i_to_a(a = a):
a.append(i)
return a
return append_i_to_a
L = []
for i in range(10):
def f():
return gen_append_i_to_a(i)()
L.append(f)
for f in L:
print(f())](https://icosahedron.website/system/media_attachments/files/114/149/327/102/288/955/original/cbe0b9c88e8008fd.png "def gen_append_i_to_a(i, a = []):
def append_i_to_a(a = a):
a.append(i)
return a
return append_i_to_a
L = []
for i in range(10):
def f():
return gen_append_i_to_a(i)()
L.append(f)
for f in L:
print(f())")
@lritter Since you're asking the question, there has to be a catch - so it's likely not 0 1 2 3 4 5 6 7 8 9, but 9 9 9 9 9 9 9 9 9 9, because the `f()` function captures only the most recent value of `i`. Another level of indirection would solve this.
(No peeking. Yet.)